Practice Final Solutions

1.  Using the ORMM queue add-in and selecting Open Network.
a) for diagnosis unit, W=0.303.  For surgery, Wq=1.196.  So total is 1.500.
b) trying different numbers of servers we find that the optimal value is 8 (4 at diagnosis, 4 surgeons).

2. True.

3. n=1000 samples, 1.96=-NORMINV(2.5%,0,1), the average = 25,531, (= 3,945
Thus the confidence interval is [25300,25800].
 
4. Newsvendor

5. Let X~Poisson(200) be a random variable.  We want to find k such that P(X>k)=1-P(X <= k-1) = 1%.  We can calculate P(X <= k-1)  using the POISSON Excel function.  k=235.

6.  0

7. 
min 5x +3y + zz
s.t. x+y+z = 5,
	zz >= z,
	zz >= -z
	x >= 0, y >= 0